Let us agree that we have a fair coin and a fair way to flip that coin. Neither of us, then, should be very surprised should a flip come up heads. Nor should either of us be very surprised should a flip come up tails.
Suppose I am surprised by an amount $s_H$ if the outcome is heads, and an amount $s_T$ if the outcome is tails. Then on average I will be surprised by an amount
$$
S = \frac{1}{2}\times s_H+\frac{1}{2}\times s_T
$$
Very reasonably, we should each be equally surprised regardless of the outcome, so $S=s_H=s_T$. Surprise is a weird thing to quantify, so let us define the surprise caused by a fair coin toss to be 1.
The surprise of two coin tosses, then should be 2, right? There are four equally likely outcomes: heads followed by heads, heads followed by tails, tails-tails, and tails-heads, so
$$
2=S=\frac{1}{4}\times s_{HH}+\frac{1}{4}\times s_{HT}+\frac{1}{4}\times s_{TT}+\frac{1}{4}\times s_{TH}
$$
and therefore equal surprise from each:
$$
S=s_{HH}=s_{HT}=s_{TT}=s_{TH}
$$
With three tosses,
$$
3=S=8\times\frac{1}{8}\times s_{ttt}
$$
and so on. The important takeaway here is that $S$ units of surprise result from realizing one of $2^S$ equally likely outcomes.
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